What happens to capacitance when the distance between plates increases?

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Multiple Choice

What happens to capacitance when the distance between plates increases?

Explanation:
Capacitance is inversely related to the plate separation. For a parallel-plate capacitor with area A and dielectric permittivity ε, C = εA/d. Keeping A and ε fixed, increasing the distance d lowers C in direct proportion. Physically, spreading the plates apart makes it harder to store the same charge at a given voltage, so the required voltage rises for the same Q, meaning C = Q/V decreases. It does not become infinite; it grows smaller as distance grows.

Capacitance is inversely related to the plate separation. For a parallel-plate capacitor with area A and dielectric permittivity ε, C = εA/d. Keeping A and ε fixed, increasing the distance d lowers C in direct proportion. Physically, spreading the plates apart makes it harder to store the same charge at a given voltage, so the required voltage rises for the same Q, meaning C = Q/V decreases. It does not become infinite; it grows smaller as distance grows.

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